Text key looks like this.
footer={communityTitle} sent this message to {Recipient}.Now I have to replace {communityTitle} with the name of the community which is available in the context object.
#set ($footer1=$footer.replace("communityTitle",${community.title}))
${footer1}Above piece of code is not working.
Any idea why?
How can I achieve this?
@petelu
Thanks for the response.
The code which I wrote also Velocity code only.
I have referred https://stackoverflow.com/questions/6843882/replace-a-substring-of-a-string-in-velocity-template-language to replace the string. But it's not working with text-keys.
It's working for a local variable like below.
#set ($abc="Hi Hello")
#set ($footer1=$abc.replace("l","p"))
${footer1}Above code prints Hi Heppo which is expected. Why it's not working text keys alone.
I have verified that text-keys are not coming null inside template.
Hi santosh_csc
this should work:
#set ($footer1 = "${footer}")
#set ($footer1=$footer1.replace("communityTitle",$community.title))
$footer1
