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VarunGrazitti's avatar
VarunGrazitti
Boss
10 years ago

Re: How to replace \" characters with ' in string using freemarker

Try using Google ASCII value or html encoded value rather than the actual backslash.

  • OlivierS's avatar
    OlivierS
    Lithium Alumni (Retired)
    10 years ago

    dhiraj_gophane or maybe try to use Regex ?

     

    From the freemarker documentation:

     

    Common flags 

    Many string built-ins accept an optional string parameter, the so called ``flags''. In this string, each letter influences a certain aspect of the behavior of the built-in. For example, letter i means that the built-in should not differentiate the lower and upper-case variation of the same letter. The order of the letters in the flags string is not significant.

    This is the complete list of letters (flags):

    • i: Case insensitive: do not differentiate the lower and upper-case variation of the same letter.

    • f: First only. That is, replace/find/etc. only the first occurrence of something.

    • r: The substring to find is a regular expression. FreeMarker uses the variation of regular expressions described at http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html (note that the presence of some pattern features depends on the Java version used).

    • m: Multi-line mode for regular expressions. In multi-line mode the expressions ^ and $match just after or just before, respectively, a line terminator or the end of the string. By default these expressions only match at the beginning and the end of the entire string. Note that ^ and $ doesn't match the line-break character itself.

    • s: Enables dot-all mode for regular expressions (same as Perl singe-line mode). In dot-all mode, the expression . matches any character, including a line terminator. By default this expression does not match line terminators.

    • c: Permits whitespace and comments in regular expressions.

     

    Example:

    <#assign s = 'foo bAr baar'>
${s?replace('ba', 'XY')}
i: ${s?replace('ba', 'XY', 'i')}
if: ${s?replace('ba', 'XY', 'if')}
r: ${s?replace('ba*', 'XY', 'r')}
ri: ${s?replace('ba*', 'XY', 'ri')}
rif: ${s?replace('ba*', 'XY', 'rif')} 

    This outputs this:

    foo bAr XYar
i: foo XYr XYar
if: foo XYr baar
r: foo XYAr XYr
ri: foo XYr XYr
rif: foo XYr baar